θ = 30°Distance (d) = 40mHeight (h) ≈ 23.09mSight (L) ≈ 46.19m
Horizontal Distance (d)40 m
Calculated Height (h)≈ 23.09 m
Line of Sight (L)≈ 46.19 m

Variable Adjuster

Observer Distance (d)40m
1580
Angle (θ)30°
1575

Auto-Sweep Engine

2x

Angle of Elevation

TRIG

Angle of elevation is measured looking upwards from a horizontal line to an object above.

tanθ=OppositeAdjacenth=dtanθ\begin{aligned}\tan\theta = \frac{\text{Opposite}}{\text{Adjacent}} \\ h = d \tan\theta\end{aligned}

Whiteboard Solver Steps

Step 1

Identify Triangle Sides

We model the scenario as a right-angled triangle where: - The horizontal distance along the ground is the Adjacent side (d=40d = 40 m). - The height of the object is the Opposite side (hh). - The angle of elevation is the angle between the horizontal line and the line of sight (θ=30\theta = 30^\circ).

Adjacent (Distance d)=40 mθ=30\begin{aligned}\text{Adjacent (Distance } d\text{)} = 40\text{ m} \\ \theta = 30^\circ\end{aligned}
Step 2

Apply Tangent Function to Find Height

Since we know the adjacent side and need the opposite side, we use the tangent trigonometric ratio: tanθ=opposite/adjacent\tan\theta = \text{opposite}/\text{adjacent}. Multiplying the distance by the tangent of the angle gives the height: h23.09h \approx 23.09 meters.

tanθ=OppositeAdjacent=hdh=d×tanθ=40×tan(30)23.09 m\begin{aligned}\tan\theta = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{h}{d} \\ h = d \times \tan\theta = 40 \times \tan(30^\circ) \approx 23.09\text{ m}\end{aligned}
Step 3

Calculate Line of Sight (Hypotenuse)

The direct line of sight from the observer to the target is the hypotenuse (LL). Using cosine (cosθ=adjacent/hypotenuse\cos\theta = \text{adjacent}/\text{hypotenuse}), we calculate the line of sight distance: L46.19L \approx 46.19 meters.

L=dcosθ=40cos(30)46.19 mL = \frac{d}{\cos\theta} = \frac{40}{\cos(30^\circ)} \approx 46.19\text{ m}